Arrange the following reagents in the correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Cyclopentanone reacts with $KOD/D_2O$ (base-catalyzed deuterium exchange) to replace all $\alpha$-hydrogens with deuterium atoms,forming

Vedclass · Accepted Answer

$KOD/D_2O, LiAlH_4, H^{+}/ \Delta$

Vedclass · Answer

(C) Step $1$: Cyclopentanone reacts with $KOD/D_2O$ (base-catalyzed deuterium exchange) to replace all $\alpha$-hydrogens with deuterium atoms,forming $2,2,5,5$-tetradeuterocyclopentanone.Step $2$: The deuterated ketone is then reduced using $LiAlH_4$ to form the corresponding alcohol,$2,2,5,5$-tetradeuterocyclopentanol.Step $3$: Finally,acid-catalyzed dehydration $(H^{+}/ \Delta)$ of the alcohol leads to the formation of the alkene product,$1,5,5$-trideuterocyclopentene (note: the product structure in the image implies the elimination of $D_2O$ or $HOD$ to form the double bond).Therefore,the correct order is $KOD/D_2O, LiAlH_4, H^{+}/ \Delta$.

Arrange the following reagents in the correct order in which the above transformation is carried out:

Similar Questions

Which of the following,on reaction with $50\%\,KOH$,gives the corresponding alcohol and acid salt?

The major product formed in the following reaction is:

The structure of the starting compound $P$ used in the reaction given below is:

Identify the product $Y$ in the following reaction sequence:
$C_6H_6 + CH_3CH_2CH_2Cl$ $\xrightarrow{AlCl_3} X$ $\xrightarrow{KMnO_4} Y$

When $(X)$ reacts with $(Y)$ in the presence of dilute $(Z)$ solution,$3-$hydroxybutanal is formed. What are $(X), (Y),$ and $(Z)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module